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2-0.25x^2=x
We move all terms to the left:
2-0.25x^2-(x)=0
We add all the numbers together, and all the variables
-0.25x^2-1x+2=0
a = -0.25; b = -1; c = +2;
Δ = b2-4ac
Δ = -12-4·(-0.25)·2
Δ = 3
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{3}}{2*-0.25}=\frac{1-\sqrt{3}}{-0.5} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{3}}{2*-0.25}=\frac{1+\sqrt{3}}{-0.5} $
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